Tugas Pertemuan 2 Jaringan Komputer Menghitung Network Dan Host Dari IP Address
Hitunglah jumlah Network dan Host yang akan terbentuk dari alamat
IP Address dibawah ini:
1. 192.168.10.1/30
2. 172.168.10.1/16
3. 172.168.10.1/22
4. 10.168.5.1/8
5. 10.168.5.1/17
Jawaban :
Nomor 1:
Netmask = 255.255.255.252
Binary = 11111111. 11111111. 11111111.11111100
Network = 2ⁿ
= 2⁶
= 64 Network
Host = 2ʰ-2
= 2²-2
= 2 Host
Nomor 2 :
Netmask = 255.255.0.0
Binary = 11111111.11111111.00000000.00000000
Network = 2ⁿ
= 2⁰
= 1 Network
Host = 2ʰ-2
= 2¹⁶-2
= 65534 Host
Nomor 3 :
Netmask : 255.255.252.0
Binary : 11111111.11111111.11111100.00000000
Network = 2ⁿ
= 2⁶
= 64 Network
Host = 2ʰ-2
= 2¹⁰-2
= 1022 Host
Nomor 4 :
Netmask : 255.0.0.0
Binary : 11111111.00000000.00000000.00000000
Network = 2ⁿ
= 2⁰
= 1 Network
Host = 2ʰ-2
= 2²⁴-2
= 167772614 Host
Nomor 5 :
Netmask : 255.255.128.0
Binary : 11111111.11111111.10000000.00000000
Network = 2ⁿ
= 2⁹
= 512 Network
Host = 2ʰ-2
= 2¹⁵-2
= 32766 Host
Netmask = 255.255.255.252
Binary = 11111111. 11111111. 11111111.11111100
Network = 2ⁿ
= 2⁶
= 64 Network
Host = 2ʰ-2
= 2²-2
= 2 Host
Nomor 2 :
Netmask = 255.255.0.0
Binary = 11111111.11111111.00000000.00000000
Network = 2ⁿ
= 2⁰
= 1 Network
Host = 2ʰ-2
= 2¹⁶-2
= 65534 Host
Nomor 3 :
Netmask : 255.255.252.0
Binary : 11111111.11111111.11111100.00000000
Network = 2ⁿ
= 2⁶
= 64 Network
Host = 2ʰ-2
= 2¹⁰-2
= 1022 Host
Nomor 4 :
Netmask : 255.0.0.0
Binary : 11111111.00000000.00000000.00000000
Network = 2ⁿ
= 2⁰
= 1 Network
Host = 2ʰ-2
= 2²⁴-2
= 167772614 Host
Nomor 5 :
Netmask : 255.255.128.0
Binary : 11111111.11111111.10000000.00000000
Network = 2ⁿ
= 2⁹
= 512 Network
Host = 2ʰ-2
= 2¹⁵-2
= 32766 Host
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